• Welcome to National Homebrew Club Ireland. Please login or sign up.
July 22, 2025, 10:43:26 PM

News:

Want to Join up ? Simply follow the instructions here
Not a forum user? Now you can join the discussion on Discord


Brewsteam

Started by DEMPSEY, April 06, 2014, 11:55:12 AM

Previous topic - Next topic

DEMPSEY

Here is a brewsteam idea,the system injects steam into the wort to bring it to boil however some aspects of it I am not too sure about. The steam replaces the boil off so you end up with the same amount of liquid at the end of the boil. The quality of the steam would be a concern after it reverts back to water :-\. The good part I can see is you could have this as entering from the top of a vessel down the centre of its lid and when boil is complete it would simply lift out leaving you with the ability to whirlpool the wort inside :). The web site posted does not exist ATM ???.
https://www.youtube.com/watch?v=MM_Hvj3xOoo
Dei miscendarum discipulus
Forgive us our Hangovers as we forgive those who hangover against us

imark

Is that brewery of yours bomb proof :P

imark

Think that video is 2 years old. The guys probably never made more than the prototype.

Sure you could knock one together with a cornie, an immersion element and a piece of string. posted and pressure release already fitted!
(I'm not being serious and would strongly advise you don't try this at home)

DEMPSEY

Me thinking is for 25 HL rather than 25 L :)
Dei miscendarum discipulus
Forgive us our Hangovers as we forgive those who hangover against us

DEMPSEY

Ok here is a question for ye Sciency types. I want to calculate how much steam I need to produce to inject into a boil kettle containing 2500 Litres. This is already at about 60 C starting.  :)
Dei miscendarum discipulus
Forgive us our Hangovers as we forgive those who hangover against us

imark

I'd say you'd be between 150 and 200L of water to steam at ~1bar at a rough estimate just to get it up to boil

DEMPSEY

Quote from: Tube on April 07, 2014, 06:21:57 PM
How about you make some more beer, rather than yokes to make beer? O0
??? :P
Dei miscendarum discipulus
Forgive us our Hangovers as we forgive those who hangover against us

Eoin

http://www.spiraxsarco.com/resources/steam-engineering-tutorials/steam-engineering-principles-and-heat-transfer/methods-of-estimating-steam-consumption.asp

In most cases, the heat in steam is required to do two things:

    To produce a change in temperature in the product, that is providing a 'heating up' component.
    To maintain the product temperature as heat is lost by natural causes or by design, that is providing a 'heat loss' component.

In any heating process, the 'heating up' component will decrease as the product temperature rises, and the differential temperature between the heating coil and the product reduces. However, the heat loss component will increase as the product temperature rises and more heat is lost to the environment from the vessel or pipework.

The total heat demand at any time is the sum of these two components.

The equation used to establish the amount of heat required to raise the temperature of a substance (Equation 2.1.4, from Tutorial 2.1), can be developed to apply to a range of heat transfer processes.
Equation 2.1.4 Equation 2.1.4

Q=McpΔT

Where:
Q   =    Quantity of energy (kJ)
m   =    Mass of the substance (kg)
cp   =    Specific heat capacity of the substance (kJ/kg °C )
ΔT   =    Temperature rise of the substance (°C)

In its original form this equation can be used to determine a total amount of heat energy over the whole process. However, in its current form, it does not take into account the rate of heat transfer. To establish the rates of heat transfer, the various types of heat exchange application can be divided into two broad categories:

    Non-flow type applications - where the product being heated is a fixed mass and a single batch within the confines of a vessel.
    Flow type applications - where a heated fluid constantly flows over the heat transfer surface.


Eoin

Q=McpΔT

Q=?
M=2500
cp=1 cal/kg needs to be converted to KJ
ΔT=40

This also takes no account of losses to the system or to the environment.



johnrm

Quote from: Eoin on April 08, 2014, 09:42:05 AM
To produce a change in temperature in the product, that is providing a 'heating up' component.
Is that comma supposed to be there?

Sorcerers Apprentice

I read it as "To produce a change in the product, ie providing a 'heating up' component"  ;D
There's no such thing as bad beer - some just taste better than others

Eoin

Quote from: johnrm on April 08, 2014, 11:25:38 PM
Quote from: Eoin on April 08, 2014, 09:42:05 AM
To produce a change in temperature in the product, that is providing a 'heating up' component.
Is that comma supposed to be there?

Yeah, but I think it's missing another one and should read.

"To produce a change in temperature in the product, that is, providing a 'heating up' component."